| 释义 |
deducededuce (something) from (something)To infer information from something. Oh, I deduced from her disinterested tone that she wouldn't be joining us today. A: "Did you know he wasn't coming?" B: "I deduced that when I saw you pull up alone." See also: deduce Farlex Dictionary of Idioms. deduce something from somethingto infer or conclude something from a set of facts. Can I deduce a bit of anger from your remarks? I deduce nothing from everything I have heard today. See also: deduce McGraw-Hill Dictionary of American Idioms and Phrasal Verbs. See also:- deduce (something) from (something)
- deduce from
- be not having any (of it)
- he, she, etc. isn't having any
- not be having any of it
- not having any
- have a bad time
- draw an inference
- infer from
- infer from (something)
References in periodicals archive As [x.sup.n] > 0, we deduce by assumption with m = 0 that f (s, [x.sup.n.sub.s]) [greater than or equal to] -[gamma][x.sup.n.sub.s] for all s [member of] [0,[T.sub.0]] hence By induction, we then deduce that [mathematical expression not reproducible] for all t [member of] [0,[T.sub.0]]. By induction, we deduce that [[parallel]x - y[parallel].sub.[0,t]] [less than or equal to] 2C[k.sup.n][t.sup.n]/n! Then, we also deduce that the sequence [([x.sup.m]).sub.m[greater than or equal to]1] uniformly converges to some function [z.sup.n] on [[t.sub.n], [t.sub.n] + [T.sup.*.sub.0]] such that Therefore, by definition of [T.sup.*], we deduce that [t.sub.n] + [T.sup.*.sub.0] [less than or equal to] [T.sup.*] for all n. A FRACTIONAL VERSION OF THE HESTON MODEL WITH HURST PARAMETER H [member of] (1/2,1) remarking via the hypotheses that 10[x.sub.n,1] = n + 71, clearly 10[x.sub.n,1] < n + 71, now using the previous inequality and (4), then it becomes trivial to deduce that statement Z([x.sub.n,1], [gamma](n), [gamma]'(n)) is true, otherwise, Z(xni1,7(n),7'(n)) is false, and using (4), then we clearly deduce that it is false that 10xn1 < n + 71, therefore, 10xn1 > n + 71. In this case, using the definition of Y([x.sub.n,1], [gamma](n), [gamma]'(n)) (see Definitions 2.1), then we immediately deduce that statement Y([x.sub.n,1], [gamma](n), [gamma]'(n)) is of the form Indeed, remarking by (5) that [MATHEMATICAL EXPRESSION NOT REPRODUCIBLE IN ASCII], and recalling that we are in the case where Z([x.sub.n,1], [gamma](n), [gamma]'(n)) is true, then, using the previous, it becomes trivial to deduce that Z([x.sub.n,1], [gamma](n), [gamma]'(n)) and Y([x.sub.n,1], [gamma](n), [gamma]'(n)), are simultaneously true. Otherwise, using the definition of statement Z([x.sub.n,1], [gamma](n), [gamma]'(n)) (see Definitions 2.1), then we immediately deduce that statement Z([x.sub.n,1], [gamma](n), [gamma]'(n)) is of the form A simple proof of the Sophie Germain primes problem along with the Mersenne primes problem and their connection to the Fermat's last conjecture Here, using only the immediate part of the generalized Fermat induction, simple definitions, elementary arithmetic congruences, elementary complex analysis, elementary arithmetic calculus, reasoning by reduction to absurd and properties (2.4) and (2.3) of Remark 2, we prove a Theorem which implies the Mersenne primes conjecture; moreover, from our Theorem, we immediately deduce that the Mersenne primes conjecture that we solved, was only an elementary consequence of the Goldbach conjecture. For that, let n + 11; recalling that in particular n is of type 37, clearly (by using the definition of type 37), n [equivalent to] 0 mod(37) and using the previous congruence, we immediately deduce that That being so, if [m.sub.n,1] <n + 11, then, using congruences (R.1.5) and (R.1.4), it becomes trivial to deduce that the previous inequality immediately implies that Now consider the quantity R[Z(n)] + I[Z(n)]; then, using (R.1.7), it becomes immediate to deduce that An elementary proof of the Mersenne primes conjecture and the connection with the Goldbach conjecture Cullen deduces what he can from prefatory references suggesting associations with the Pierrepont family of Dorchester and with James Howell, author of Dodona's Grove; other scholars will no doubt discover additional facts in due course. A Continuation of Sir Philip Sidney's Arcadia He insists on a dark power as the cause and iconography of men in black: "Alone or in ranks, the man in black is the agent of a serious power; and of a power claimed over women and the feminine." Accordingly, he deduces gravely, "We live now in the aftertow of the black wave's latest rise and breaking.... Men in Black |